10x^2-12x-20=0

Solution for 10x^2-12x-20=0 equation:

10x^2-12x-20=0

a = 10; b = -12; c = -20;
Δ = b2-4ac
Δ = -122-4·10·(-20)
Δ = 944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{944}=\sqrt{16*59}=\sqrt{16}*\sqrt{59}=4\sqrt{59}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{59}}{2*10}=\frac{12-4\sqrt{59}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{59}}{2*10}=\frac{12+4\sqrt{59}}{20}
$